Foot-Pounds Force (ft·lbf) to Calories (cal) Converter
Enter a value to instantly convert between energy units.
1 Foot-Pound Force = 0.324 Calorie (thermochemical)
Key Formulas
Kilocalorie → Kilojoule
kJ = kcal × 4.184Kilojoule → Kilocalorie
kcal = kJ × 0.239006Kilowatt-Hour → Joule
J = kWh × 3600000Joule → Kilowatt-Hour
kWh = J × 2.77778e-7Formula
cal = ft·lbf × 0.3239One foot-pound force equals 0.3239 thermochemical calories. Since 1 ft·lbf = 1.356 J and 1 cal = 4.184 J, the conversion is 1.356/4.184 = 0.3239 cal per ft·lbf. This connects mechanical work to heat energy.
Source: NIST SP 811, Table B.8
Frequently Asked Questions
Real-World Examples
A mechanical engineer calculating 100 ft·lbf of work equals 32.4 cal for the analysis.
100 ft·lbf = 32.39 cal
A fitness coach explaining that 1000 ft·lbf of mechanical work (lifting 100 lbs 10 ft) burns 324 cal.
1000 ft·lbf = 323.9 cal
A student converting 10 ft·lbf to calories for a thermodynamics problem — 3.24 cal.
10 ft·lbf = 3.239 cal
A horse pumping 550 ft·lbf per second (1 hp) produces 178 cal per second — about 10,680 cal/min.
550 ft·lbf = 178.1 cal